bootstrap: Remove check that identifies GNU compiler

Bootstrapping no longer depends on this information.

1 files changed, 0 insertions, 25 deletions

diff --git a/bootstrap b/bootstrap
index 7304908..00c3ba5 100755
--- a/bootstrap
+++ b/bootstrap
@@ -1110,31 +1110,6 @@ if [ "x${cmake_full_make_flags}" != "x${cmake_make_flags}" ]; then
   echo "---------------------------------------------"
 fi
 
-# Ok, we have CC, CXX, and MAKE.
-
-# Test C++ compiler features
-
-# Are we GCC?
-
-TMPFILE=`cmake_tmp_file`
-echo '
-#if defined(__GNUC__) && !defined(__INTEL_COMPILER)
-#include <iostream>
-int main() { std::cout << "This is GNU" << std::endl; return 0;}
-#endif
-' > ${TMPFILE}.cxx
-cmake_cxx_compiler_is_gnu=0
-if cmake_try_run "${cmake_cxx_compiler}" \
-  "${cmake_cxx_flags}" "${TMPFILE}.cxx" >> cmake_bootstrap.log 2>&1; then
-  cmake_cxx_compiler_is_gnu=1
-fi
-if [ "x${cmake_cxx_compiler_is_gnu}" = "x1" ]; then
-  echo "${cmake_cxx_compiler} is GNU compiler"
-else
-  echo "${cmake_cxx_compiler} is not GNU compiler"
-fi
-rm -f "${TMPFILE}.cxx"
-
 # Test for kwsys features
 KWSYS_NAME_IS_KWSYS=0
 KWSYS_BUILD_SHARED=0