Don't interrupt test before animation finishes

We're testing if both animations actually run and finish, so we need to make
sure one of the polished signals is emitted last, and then react to this. I've
done this by setting the duration of the animation which animated the property
set by s2Child, so that it's sufficient to listen to this polished signal.

1 files changed, 4 insertions, 2 deletions

diff --git a/tests/auto/qstatemachine/tst_qstatemachine.cpp b/tests/auto/qstatemachine/tst_qstatemachine.cpp
index d24a945..9058cb6 100644
--- a/tests/auto/qstatemachine/tst_qstatemachine.cpp
+++ b/tests/auto/qstatemachine/tst_qstatemachine.cpp
@@ -2529,6 +2529,7 @@ void tst_QStateMachine::nestedTargetStateForAnimation()
     QAbstractTransition *at = s2Child->addTransition(new EventTransition(QEvent::User, s2Child2));
     
     QPropertyAnimation *animation = new QPropertyAnimation(object, "bar", s2);
+    animation->setDuration(2000);
     connect(animation, SIGNAL(finished()), &counter, SLOT(slot()));
     at->addAnimation(animation);
     
@@ -2541,10 +2542,11 @@ void tst_QStateMachine::nestedTargetStateForAnimation()
     animation = new QPropertyAnimation(object, "bar", s2);
     connect(animation, SIGNAL(finished()), &counter, SLOT(slot()));
     at->addAnimation(animation);
-
+    
     QState *s3 = new QState(machine.rootState());
+    s2->addTransition(s2Child, SIGNAL(polished()), s3);
+
     QObject::connect(s3, SIGNAL(entered()), QCoreApplication::instance(), SLOT(quit()));
-    s2->addTransition(s2, SIGNAL(polished()), s3);
 
     machine.setInitialState(s1);
     machine.start();