Cocoa: Active QDockWidget does not stay on top of inactive QDockWidget

If a window has several child windows, it was not be possible to
click on a child window to make it stack in front of the other
children. The reason is that cocoa held a fixed stacking order of
the child windows (sub-windows). This patch will release, and then
reestablish, the stacking order of the children upon acitvation.

Task-number: QTBUG-11780
Reviewed-by: prasanth

1 files changed, 7 insertions, 0 deletions

diff --git a/src/gui/kernel/qapplication.cpp b/src/gui/kernel/qapplication.cpp
index 5c333b0..3303800 100644
--- a/src/gui/kernel/qapplication.cpp
+++ b/src/gui/kernel/qapplication.cpp
@@ -2540,6 +2540,13 @@ void QApplication::setActiveWindow(QWidget* act)
         sendSpontaneousEvent(w, &activationChange);
     }
 
+#ifdef QT_MAC_USE_COCOA
+    // In case the user clicked on a child window, we need to
+    // reestablish the stacking order of the window so
+    // it pops in front of other child windows in cocoa:
+    qt_cocoaStackChildWindowOnTopOfOtherChildren(window);
+#endif
+
     for(int i = 0; i < toBeDeactivated.size(); ++i) {
         QWidget *w = toBeDeactivated.at(i);
         sendSpontaneousEvent(w, &windowDeactivate);