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authorBrett Cannon <bcannon@gmail.com>2007-09-10 21:38:27 (GMT)
committerBrett Cannon <bcannon@gmail.com>2007-09-10 21:38:27 (GMT)
commita0c05512ec071b98e8170c8cfe845bee6fc934da (patch)
tree83da314bd97dd8153e1ffd85f933c24087fae956
parentf3d280e62acfa2d597dff13105f7fec4a5eeb8e6 (diff)
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Fix a possible segfault from recursing too deep to get the repr of a list.
Closes issue #1096.
-rw-r--r--Lib/test/list_tests.py5
-rw-r--r--Misc/NEWS3
-rw-r--r--Objects/listobject.c3
3 files changed, 11 insertions, 0 deletions
diff --git a/Lib/test/list_tests.py b/Lib/test/list_tests.py
index 1c799d7..a0011a4 100644
--- a/Lib/test/list_tests.py
+++ b/Lib/test/list_tests.py
@@ -46,6 +46,11 @@ class CommonTest(seq_tests.CommonTest):
self.assertEqual(str(a2), "[0, 1, 2, [...], 3]")
self.assertEqual(repr(a2), "[0, 1, 2, [...], 3]")
+ l0 = []
+ for i in xrange(sys.getrecursionlimit() + 100):
+ l0 = [l0]
+ self.assertRaises(RuntimeError, repr, l0)
+
def test_print(self):
d = self.type2test(xrange(200))
d.append(d)
diff --git a/Misc/NEWS b/Misc/NEWS
index 99e4f07..10f2c71 100644
--- a/Misc/NEWS
+++ b/Misc/NEWS
@@ -12,6 +12,9 @@ What's New in Python 2.6 alpha 1?
Core and builtins
-----------------
+- Issue #1096: Prevent a segfault from getting the repr of a very deeply nested
+ list by using the recursion counter.
+
- Issue #1202533: Fix infinite recursion calls triggered by calls to
PyObject_Call() never calling back out to Python code to trigger recursion
depth updates/checks. Required the creation of a static RuntimeError
diff --git a/Objects/listobject.c b/Objects/listobject.c
index c0621dc..92bad8c 100644
--- a/Objects/listobject.c
+++ b/Objects/listobject.c
@@ -324,7 +324,10 @@ list_repr(PyListObject *v)
so must refetch the list size on each iteration. */
for (i = 0; i < Py_Size(v); ++i) {
int status;
+ if (Py_EnterRecursiveCall(" while getting the repr of a list"))
+ goto Done;
s = PyObject_Repr(v->ob_item[i]);
+ Py_LeaveRecursiveCall();
if (s == NULL)
goto Done;
status = PyList_Append(pieces, s);