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authorRaymond Hettinger <rhettinger@users.noreply.github.com>2019-02-21 17:19:00 (GMT)
committerGitHub <noreply@github.com>2019-02-21 17:19:00 (GMT)
commit407c7343266eb3e5a2f5c1f4913082c84f8dd8a0 (patch)
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bpo-36057 Update docs and tests for ordering in collections.Counter [no behavior change] (#11962)
* Add tests for Counter order. No behavior change. * Update docs and tests * Fix doctest output and capitalization
Diffstat (limited to 'Doc/library/collections.rst')
-rw-r--r--Doc/library/collections.rst15
1 files changed, 10 insertions, 5 deletions
diff --git a/Doc/library/collections.rst b/Doc/library/collections.rst
index ca2f116..1a09379 100644
--- a/Doc/library/collections.rst
+++ b/Doc/library/collections.rst
@@ -268,6 +268,11 @@ For example::
.. versionadded:: 3.1
+ .. versionchanged:: 3.7 As a :class:`dict` subclass, :class:`Counter`
+ Inherited the capability to remember insertion order. Math operations
+ on *Counter* objects also preserve order. Results are ordered
+ according to when an element is first encountered in the left operand
+ and then by the order encountered in the right operand.
Counter objects support three methods beyond those available for all
dictionaries:
@@ -275,8 +280,8 @@ For example::
.. method:: elements()
Return an iterator over elements repeating each as many times as its
- count. Elements are returned in arbitrary order. If an element's count
- is less than one, :meth:`elements` will ignore it.
+ count. Elements are returned in the order first encountered. If an
+ element's count is less than one, :meth:`elements` will ignore it.
>>> c = Counter(a=4, b=2, c=0, d=-2)
>>> sorted(c.elements())
@@ -287,10 +292,10 @@ For example::
Return a list of the *n* most common elements and their counts from the
most common to the least. If *n* is omitted or ``None``,
:meth:`most_common` returns *all* elements in the counter.
- Elements with equal counts are ordered arbitrarily:
+ Elements with equal counts are ordered in the order first encountered:
- >>> Counter('abracadabra').most_common(3) # doctest: +SKIP
- [('a', 5), ('r', 2), ('b', 2)]
+ >>> Counter('abracadabra').most_common(3)
+ [('a', 5), ('b', 2), ('r', 2)]
.. method:: subtract([iterable-or-mapping])