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authorEzio Melotti <ezio.melotti@gmail.com>2011-10-19 07:58:56 (GMT)
committerEzio Melotti <ezio.melotti@gmail.com>2011-10-19 07:58:56 (GMT)
commite130a52d8a60229f53c8bc2ea7a1f51ee592bbd7 (patch)
treeb7f128d5f626c78d57d53812a5953c6eb56cca72 /Lib/datetime.py
parenta5a9a9c3696af0a4a0df74618e63a4d47a62e00f (diff)
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Remove duplication.
Diffstat (limited to 'Lib/datetime.py')
-rw-r--r--Lib/datetime.py2
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diff --git a/Lib/datetime.py b/Lib/datetime.py
index 1ae7cb5..65f95d2 100644
--- a/Lib/datetime.py
+++ b/Lib/datetime.py
@@ -2057,7 +2057,7 @@ z' = z + z.d = 1:MM then, and z'.d=0, and z'.d - z.d = -60 != 0 so [8]
Because we know z.d said z was in daylight time (else [5] would have held and
we would have stopped then), and we know z.d != z'.d (else [8] would have held
-and we we have stopped then), and there are only 2 possible values dst() can
+and we have stopped then), and there are only 2 possible values dst() can
return in Eastern, it follows that z'.d must be 0 (which it is in the example,
but the reasoning doesn't depend on the example -- it depends on there being
two possible dst() outcomes, one zero and the other non-zero). Therefore