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authorSerhiy Storchaka <storchaka@gmail.com>2014-01-27 21:15:14 (GMT)
committerSerhiy Storchaka <storchaka@gmail.com>2014-01-27 21:15:14 (GMT)
commitc369c2c688c407433d88a7cad75cda88fbe799b5 (patch)
tree4b2952e461ada005e6e8b1953a6aef204af2ddff /Lib/ntpath.py
parent99e033b02e9f352c484e20d6a6d57954304865b4 (diff)
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Issue #19456: ntpath.join() now joins relative paths correctly when a drive
is present.
Diffstat (limited to 'Lib/ntpath.py')
-rw-r--r--Lib/ntpath.py106
1 files changed, 30 insertions, 76 deletions
diff --git a/Lib/ntpath.py b/Lib/ntpath.py
index b05436e..5a012bd 100644
--- a/Lib/ntpath.py
+++ b/Lib/ntpath.py
@@ -104,82 +104,36 @@ def isabs(s):
# Join two (or more) paths.
-
-def join(a, *p):
- """Join two or more pathname components, inserting "\\" as needed.
- If any component is an absolute path, all previous path components
- will be discarded."""
- sep = _get_sep(a)
- seps = _get_bothseps(a)
- colon = _get_colon(a)
- path = a
- for b in p:
- b_wins = 0 # set to 1 iff b makes path irrelevant
- if not path:
- b_wins = 1
-
- elif isabs(b):
- # This probably wipes out path so far. However, it's more
- # complicated if path begins with a drive letter. You get a+b
- # (minus redundant slashes) in these four cases:
- # 1. join('c:', '/a') == 'c:/a'
- # 2. join('//computer/share', '/a') == '//computer/share/a'
- # 3. join('c:/', '/a') == 'c:/a'
- # 4. join('//computer/share/', '/a') == '//computer/share/a'
- # But b wins in all of these cases:
- # 5. join('c:/a', '/b') == '/b'
- # 6. join('//computer/share/a', '/b') == '/b'
- # 7. join('c:', 'd:/') == 'd:/'
- # 8. join('c:', '//computer/share/') == '//computer/share/'
- # 9. join('//computer/share', 'd:/') == 'd:/'
- # 10. join('//computer/share', '//computer/share/') == '//computer/share/'
- # 11. join('c:/', 'd:/') == 'd:/'
- # 12. join('c:/', '//computer/share/') == '//computer/share/'
- # 13. join('//computer/share/', 'd:/') == 'd:/'
- # 14. join('//computer/share/', '//computer/share/') == '//computer/share/'
- b_prefix, b_rest = splitdrive(b)
-
- # if b has a prefix, it always wins.
- if b_prefix:
- b_wins = 1
- else:
- # b doesn't have a prefix.
- # but isabs(b) returned true.
- # and therefore b_rest[0] must be a slash.
- # (but let's check that.)
- assert(b_rest and b_rest[0] in seps)
-
- # so, b still wins if path has a rest that's more than a sep.
- # you get a+b if path_rest is empty or only has a sep.
- # (see cases 1-4 for times when b loses.)
- path_rest = splitdrive(path)[1]
- b_wins = path_rest and path_rest not in seps
-
- if b_wins:
- path = b
- else:
- # Join, and ensure there's a separator.
- assert len(path) > 0
- if path[-1:] in seps:
- if b and b[:1] in seps:
- path += b[1:]
- else:
- path += b
- elif path[-1:] == colon:
- path += b
- elif b:
- if b[:1] in seps:
- path += b
- else:
- path += sep + b
- else:
- # path is not empty and does not end with a backslash,
- # but b is empty; since, e.g., split('a/') produces
- # ('a', ''), it's best if join() adds a backslash in
- # this case.
- path += sep
-
- return path
+def join(path, *paths):
+ sep = _get_sep(path)
+ seps = _get_bothseps(path)
+ colon = _get_colon(path)
+ result_drive, result_path = splitdrive(path)
+ for p in paths:
+ p_drive, p_path = splitdrive(p)
+ if p_path and p_path[0] in seps:
+ # Second path is absolute
+ if p_drive or not result_drive:
+ result_drive = p_drive
+ result_path = p_path
+ continue
+ elif p_drive and p_drive != result_drive:
+ if p_drive.lower() != result_drive.lower():
+ # Different drives => ignore the first path entirely
+ result_drive = p_drive
+ result_path = p_path
+ continue
+ # Same drive in different case
+ result_drive = p_drive
+ # Second path is relative to the first
+ if result_path and result_path[-1] not in seps:
+ result_path = result_path + sep
+ result_path = result_path + p_path
+ ## add separator between UNC and non-absolute path
+ if (result_path and result_path[0] not in seps and
+ result_drive and result_drive[-1:] != colon):
+ return result_drive + sep + result_path
+ return result_drive + result_path
# Split a path in a drive specification (a drive letter followed by a