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author | Min ho Kim <minho42@gmail.com> | 2019-07-05 21:39:32 (GMT) |
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committer | Brett Cannon <54418+brettcannon@users.noreply.github.com> | 2019-07-05 21:39:32 (GMT) |
commit | f7d72e48fb235684e17668a1e5107e6b0dab7b80 (patch) | |
tree | 58999471e0bd6bd96173f4b1039b82526a13c85d /Modules/mathmodule.c | |
parent | 10e5c66789a06dc9015a24968e96e77a75725a7a (diff) | |
download | cpython-f7d72e48fb235684e17668a1e5107e6b0dab7b80.zip cpython-f7d72e48fb235684e17668a1e5107e6b0dab7b80.tar.gz cpython-f7d72e48fb235684e17668a1e5107e6b0dab7b80.tar.bz2 |
Fix some typos (GH-14435)
Diffstat (limited to 'Modules/mathmodule.c')
-rw-r--r-- | Modules/mathmodule.c | 2 |
1 files changed, 1 insertions, 1 deletions
diff --git a/Modules/mathmodule.c b/Modules/mathmodule.c index a75a3c9..552cb78 100644 --- a/Modules/mathmodule.c +++ b/Modules/mathmodule.c @@ -1552,7 +1552,7 @@ prove that after that line is executed, we have (a - 1)**2 < (n >> 2*(c - d)) < (a + 1)**2 -To faciliate the proof, we make some changes of notation. Write `m` for +To facilitate the proof, we make some changes of notation. Write `m` for `n >> 2*(c-d)`, and write `b` for the new value of `a`, so b = (a << d - e - 1) + (n >> 2*c - e - d + 1) // a |