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authorRaymond Hettinger <python@rcn.com>2004-02-10 09:25:40 (GMT)
committerRaymond Hettinger <python@rcn.com>2004-02-10 09:25:40 (GMT)
commit5cab2e3a88903b0cea558ee01b8f5b9e5a31a797 (patch)
tree520d1fdfefd2c4104669ad18fc30e0e86dbadc2c /Modules
parent27da291b2c2b32b0f976bb7599f6e9b2d07e6e4c (diff)
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Give itertools.repeat() a length method.
Diffstat (limited to 'Modules')
-rw-r--r--Modules/itertoolsmodule.c15
1 files changed, 14 insertions, 1 deletions
diff --git a/Modules/itertoolsmodule.c b/Modules/itertoolsmodule.c
index 387133c..ebd5f6d 100644
--- a/Modules/itertoolsmodule.c
+++ b/Modules/itertoolsmodule.c
@@ -2347,6 +2347,19 @@ repeat_next(repeatobject *ro)
return ro->element;
}
+static int
+repeat_len(repeatobject *ro)
+{
+ if (ro->cnt == -1)
+ PyErr_SetString(PyExc_TypeError, "len() of unsized object");
+ return (int)(ro->cnt);
+}
+
+static PySequenceMethods repeat_as_sequence = {
+ (inquiry)repeat_len, /* sq_length */
+ 0, /* sq_concat */
+};
+
PyDoc_STRVAR(repeat_doc,
"repeat(element [,times]) -> create an iterator which returns the element\n\
for the specified number of times. If not specified, returns the element\n\
@@ -2366,7 +2379,7 @@ static PyTypeObject repeat_type = {
0, /* tp_compare */
0, /* tp_repr */
0, /* tp_as_number */
- 0, /* tp_as_sequence */
+ &repeat_as_sequence, /* tp_as_sequence */
0, /* tp_as_mapping */
0, /* tp_hash */
0, /* tp_call */