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author | Victor Stinner <victor.stinner@gmail.com> | 2017-10-24 23:53:32 (GMT) |
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committer | GitHub <noreply@github.com> | 2017-10-24 23:53:32 (GMT) |
commit | 850a18e03e8f8309bc8c39adc6e7d51a4568cd9a (patch) | |
tree | 56455b89cb152566734d1fc5de5c70029c3baa70 /Python/thread_nt.h | |
parent | 3557b05c5a7dfd7d97ddfd3b79aefd53d25e5132 (diff) | |
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bpo-30768: Recompute timeout on interrupted lock (GH-4103)
Fix the pthread+semaphore implementation of
PyThread_acquire_lock_timed() when called with timeout > 0 and
intr_flag=0: recompute the timeout if sem_timedwait() is interrupted
by a signal (EINTR).
See also the PEP 475.
The pthread implementation of PyThread_acquire_lock() now fails with
a fatal error if the timeout is larger than PY_TIMEOUT_MAX, as done
in the Windows implementation.
The check prevents any risk of overflow in PyThread_acquire_lock().
Add also PY_DWORD_MAX constant.
Diffstat (limited to 'Python/thread_nt.h')
-rw-r--r-- | Python/thread_nt.h | 9 |
1 files changed, 5 insertions, 4 deletions
diff --git a/Python/thread_nt.h b/Python/thread_nt.h index bae8bcc..46df346 100644 --- a/Python/thread_nt.h +++ b/Python/thread_nt.h @@ -283,12 +283,13 @@ PyThread_acquire_lock_timed(PyThread_type_lock aLock, milliseconds = microseconds / 1000; if (microseconds % 1000 > 0) ++milliseconds; - if ((DWORD) milliseconds != milliseconds) - Py_FatalError("Timeout too large for a DWORD, " - "please check PY_TIMEOUT_MAX"); + if (milliseconds > PY_DWORD_MAX) { + Py_FatalError("Timeout larger than PY_TIMEOUT_MAX"); + } } - else + else { milliseconds = INFINITE; + } dprintf(("%lu: PyThread_acquire_lock_timed(%p, %lld) called\n", PyThread_get_thread_ident(), aLock, microseconds)); |