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| -rw-r--r-- | Doc/faq/programming.rst | 15 | ||||
| -rw-r--r-- | Misc/NEWS.d/next/Documentation/2020-09-24-15-35-13.bpo-41774.5IqdGP.rst | 2 |
2 files changed, 17 insertions, 0 deletions
diff --git a/Doc/faq/programming.rst b/Doc/faq/programming.rst index 66d210a..1435765 100644 --- a/Doc/faq/programming.rst +++ b/Doc/faq/programming.rst @@ -1164,6 +1164,21 @@ This converts the list into a set, thereby removing duplicates, and then back into a list. +How do you remove multiple items from a list +-------------------------------------------- + +As with removing duplicates, explicitly iterating in reverse with a +delete condition is one possibility. However, it is easier and faster +to use slice replacement with an implicit or explicit forward iteration. +Here are three variations.:: + + mylist[:] = filter(keep_function, mylist) + mylist[:] = (x for x in mylist if keep_condition) + mylist[:] = [x for x in mylist if keep_condition] + +If space is not an issue, the list comprehension may be fastest. + + How do you make an array in Python? ----------------------------------- diff --git a/Misc/NEWS.d/next/Documentation/2020-09-24-15-35-13.bpo-41774.5IqdGP.rst b/Misc/NEWS.d/next/Documentation/2020-09-24-15-35-13.bpo-41774.5IqdGP.rst new file mode 100644 index 0000000..af8e024 --- /dev/null +++ b/Misc/NEWS.d/next/Documentation/2020-09-24-15-35-13.bpo-41774.5IqdGP.rst @@ -0,0 +1,2 @@ +In Programming FAQ "Sequences (Tuples/Lists)" section, add "How do you +remove multiple items from a list". |