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-rw-r--r--Lib/difflib.py65
1 files changed, 45 insertions, 20 deletions
diff --git a/Lib/difflib.py b/Lib/difflib.py
index 55f69ba..3e28b18 100644
--- a/Lib/difflib.py
+++ b/Lib/difflib.py
@@ -86,8 +86,7 @@ class SequenceMatcher:
>>> for block in s.get_matching_blocks():
... print "a[%d] and b[%d] match for %d elements" % block
a[0] and b[0] match for 8 elements
- a[8] and b[17] match for 6 elements
- a[14] and b[23] match for 15 elements
+ a[8] and b[17] match for 21 elements
a[29] and b[38] match for 0 elements
Note that the last tuple returned by .get_matching_blocks() is always a
@@ -101,8 +100,7 @@ class SequenceMatcher:
... print "%6s a[%d:%d] b[%d:%d]" % opcode
equal a[0:8] b[0:8]
insert a[8:8] b[8:17]
- equal a[8:14] b[17:23]
- equal a[14:29] b[23:38]
+ equal a[8:29] b[17:38]
See the Differ class for a fancy human-friendly file differencer, which
uses SequenceMatcher both to compare sequences of lines, and to compare
@@ -461,7 +459,11 @@ class SequenceMatcher:
Each triple is of the form (i, j, n), and means that
a[i:i+n] == b[j:j+n]. The triples are monotonically increasing in
- i and in j.
+ i and in j. New in Python 2.5, it's also guaranteed that if
+ (i, j, n) and (i', j', n') are adjacent triples in the list, and
+ the second is not the last triple in the list, then i+n != i' or
+ j+n != j'. IOW, adjacent triples never describe adjacent equal
+ blocks.
The last triple is a dummy, (len(a), len(b), 0), and is the only
triple with n==0.
@@ -475,28 +477,52 @@ class SequenceMatcher:
return self.matching_blocks
la, lb = len(self.a), len(self.b)
- indexed_blocks = []
+ # This is most naturally expressed as a recursive algorithm, but
+ # at least one user bumped into extreme use cases that exceeded
+ # the recursion limit on their box. So, now we maintain a list
+ # ('queue`) of blocks we still need to look at, and append partial
+ # results to `matching_blocks` in a loop; the matches are sorted
+ # at the end.
queue = [(0, la, 0, lb)]
+ matching_blocks = []
while queue:
- # builds list of matching blocks covering a[alo:ahi] and
- # b[blo:bhi], appending them in increasing order to answer
alo, ahi, blo, bhi = queue.pop()
-
+ i, j, k = x = self.find_longest_match(alo, ahi, blo, bhi)
# a[alo:i] vs b[blo:j] unknown
# a[i:i+k] same as b[j:j+k]
# a[i+k:ahi] vs b[j+k:bhi] unknown
- i, j, k = x = self.find_longest_match(alo, ahi, blo, bhi)
-
- if k:
+ if k: # if k is 0, there was no matching block
+ matching_blocks.append(x)
if alo < i and blo < j:
queue.append((alo, i, blo, j))
- indexed_blocks.append((i, x))
if i+k < ahi and j+k < bhi:
queue.append((i+k, ahi, j+k, bhi))
- indexed_blocks.sort()
-
- self.matching_blocks = [elem[1] for elem in indexed_blocks]
- self.matching_blocks.append( (la, lb, 0) )
+ matching_blocks.sort()
+
+ # It's possible that we have adjacent equal blocks in the
+ # matching_blocks list now. Starting with 2.5, this code was added
+ # to collapse them.
+ i1 = j1 = k1 = 0
+ non_adjacent = []
+ for i2, j2, k2 in matching_blocks:
+ # Is this block adjacent to i1, j1, k1?
+ if i1 + k1 == i2 and j1 + k1 == j2:
+ # Yes, so collapse them -- this just increases the length of
+ # the first block by the length of the second, and the first
+ # block so lengthened remains the block to compare against.
+ k1 += k2
+ else:
+ # Not adjacent. Remember the first block (k1==0 means it's
+ # the dummy we started with), and make the second block the
+ # new block to compare against.
+ if k1:
+ non_adjacent.append((i1, j1, k1))
+ i1, j1, k1 = i2, j2, k2
+ if k1:
+ non_adjacent.append((i1, j1, k1))
+
+ non_adjacent.append( (la, lb, 0) )
+ self.matching_blocks = non_adjacent
return self.matching_blocks
def get_opcodes(self):
@@ -1422,8 +1448,7 @@ def _mdiff(fromlines, tolines, context=None, linejunk=None,
num_blanks_pending -= 1
yield _make_line(lines,'-',0), None, True
continue
- elif s.startswith('--?+') or s.startswith('--+') or \
- s.startswith('- '):
+ elif s.startswith(('--?+', '--+', '- ')):
# in delete block and see a intraline change or unchanged line
# coming: yield the delete line and then blanks
from_line,to_line = _make_line(lines,'-',0), None
@@ -1447,7 +1472,7 @@ def _mdiff(fromlines, tolines, context=None, linejunk=None,
num_blanks_pending += 1
yield None, _make_line(lines,'+',1), True
continue
- elif s.startswith('+ ') or s.startswith('+-'):
+ elif s.startswith(('+ ', '+-')):
# will be leaving an add block: yield blanks then add line
from_line, to_line = None, _make_line(lines,'+',1)
num_blanks_to_yield,num_blanks_pending = num_blanks_pending+1,0