diff options
Diffstat (limited to 'Modules')
| -rw-r--r-- | Modules/_abc.c | 4 | ||||
| -rw-r--r-- | Modules/mathmodule.c | 2 |
2 files changed, 3 insertions, 3 deletions
diff --git a/Modules/_abc.c b/Modules/_abc.c index 7233690..219ea0d 100644 --- a/Modules/_abc.c +++ b/Modules/_abc.c @@ -554,7 +554,7 @@ end: } -// Return -1 when exception occured. +// Return -1 when exception occurred. // Return 1 when result is set. // Return 0 otherwise. static int subclasscheck_check_registry(_abc_data *impl, PyObject *subclass, @@ -666,7 +666,7 @@ _abc__abc_subclasscheck_impl(PyObject *module, PyObject *self, /* 5. Check if it's a subclass of a registered class (recursive). */ if (subclasscheck_check_registry(impl, subclass, &result)) { - // Exception occured or result is set. + // Exception occurred or result is set. goto end; } diff --git a/Modules/mathmodule.c b/Modules/mathmodule.c index a75a3c9..552cb78 100644 --- a/Modules/mathmodule.c +++ b/Modules/mathmodule.c @@ -1552,7 +1552,7 @@ prove that after that line is executed, we have (a - 1)**2 < (n >> 2*(c - d)) < (a + 1)**2 -To faciliate the proof, we make some changes of notation. Write `m` for +To facilitate the proof, we make some changes of notation. Write `m` for `n >> 2*(c-d)`, and write `b` for the new value of `a`, so b = (a << d - e - 1) + (n >> 2*c - e - d + 1) // a |