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-rw-r--r--Python/thread_os2.h51
1 files changed, 34 insertions, 17 deletions
diff --git a/Python/thread_os2.h b/Python/thread_os2.h
index 0709e06..d95d765 100644
--- a/Python/thread_os2.h
+++ b/Python/thread_os2.h
@@ -29,14 +29,16 @@ long PyThread_get_thread_ident(void);
/*
* Initialization of the C package, should not be needed.
*/
-static void PyThread__init_thread(void)
+static void
+PyThread__init_thread(void)
{
}
/*
* Thread support.
*/
-int PyThread_start_new_thread(void (*func)(void *), void *arg)
+int
+PyThread_start_new_thread(void (*func)(void *), void *arg)
{
int aThread;
int success = 1;
@@ -52,7 +54,8 @@ int PyThread_start_new_thread(void (*func)(void *), void *arg)
return success;
}
-long PyThread_get_thread_ident(void)
+long
+PyThread_get_thread_ident(void)
{
PPIB pib;
PTIB tib;
@@ -64,7 +67,8 @@ long PyThread_get_thread_ident(void)
return tib->tib_ptib2->tib2_ultid;
}
-static void do_PyThread_exit_thread(int no_cleanup)
+static void
+do_PyThread_exit_thread(int no_cleanup)
{
dprintf(("%ld: PyThread_exit_thread called\n", PyThread_get_thread_ident()));
if (!initialized)
@@ -75,18 +79,21 @@ static void do_PyThread_exit_thread(int no_cleanup)
_endthread();
}
-void PyThread_exit_thread(void)
+void
+PyThread_exit_thread(void)
{
do_PyThread_exit_thread(0);
}
-void PyThread__exit_thread(void)
+void
+PyThread__exit_thread(void)
{
do_PyThread_exit_thread(1);
}
#ifndef NO_EXIT_PROG
-static void do_PyThread_exit_prog(int status, int no_cleanup)
+static void
+do_PyThread_exit_prog(int status, int no_cleanup)
{
dprintf(("PyThread_exit_prog(%d) called\n", status));
if (!initialized)
@@ -96,12 +103,14 @@ static void do_PyThread_exit_prog(int status, int no_cleanup)
exit(status);
}
-void PyThread_exit_prog(int status)
+void
+PyThread_exit_prog(int status)
{
do_PyThread_exit_prog(status, 0);
}
-void PyThread__exit_prog _P1(int status)
+void
+PyThread__exit_prog(int status)
{
do_PyThread_exit_prog(status, 1);
}
@@ -112,7 +121,8 @@ void PyThread__exit_prog _P1(int status)
* I [Dag] tried to implement it with mutex but I could find a way to
* tell whether a thread already own the lock or not.
*/
-PyThread_type_lock PyThread_allocate_lock(void)
+PyThread_type_lock
+PyThread_allocate_lock(void)
{
HMTX aLock;
APIRET rc;
@@ -131,7 +141,8 @@ PyThread_type_lock PyThread_allocate_lock(void)
return (PyThread_type_lock) aLock;
}
-void PyThread_free_lock(PyThread_type_lock aLock)
+void
+PyThread_free_lock(PyThread_type_lock aLock)
{
dprintf(("%ld: PyThread_free_lock(%p) called\n", PyThread_get_thread_ident(),aLock));
@@ -144,7 +155,8 @@ void PyThread_free_lock(PyThread_type_lock aLock)
* and 0 if the lock was not acquired. This means a 0 is returned
* if the lock has already been acquired by this thread!
*/
-int PyThread_acquire_lock(PyThread_type_lock aLock, int waitflag)
+int
+PyThread_acquire_lock(PyThread_type_lock aLock, int waitflag)
{
int success = 1;
ULONG rc, count;
@@ -172,7 +184,8 @@ int PyThread_acquire_lock(PyThread_type_lock aLock, int waitflag)
return success;
}
-void PyThread_release_lock(PyThread_type_lock aLock)
+void
+PyThread_release_lock(PyThread_type_lock aLock)
{
dprintf(("%ld: PyThread_release_lock(%p) called\n", PyThread_get_thread_ident(),aLock));
@@ -185,22 +198,26 @@ void PyThread_release_lock(PyThread_type_lock aLock)
/*
* Semaphore support.
*/
-PyThread_type_sema PyThread_allocate_sema(int value)
+PyThread_type_sema
+PyThread_allocate_sema(int value)
{
return (PyThread_type_sema) 0;
}
-void PyThread_free_sema(PyThread_type_sema aSemaphore)
+void
+PyThread_free_sema(PyThread_type_sema aSemaphore)
{
}
-int PyThread_down_sema(PyThread_type_sema aSemaphore, int waitflag)
+int
+PyThread_down_sema(PyThread_type_sema aSemaphore, int waitflag)
{
return -1;
}
-void PyThread_up_sema(PyThread_type_sema aSemaphore)
+void
+PyThread_up_sema(PyThread_type_sema aSemaphore)
{
dprintf(("%ld: PyThread_up_sema(%p)\n", PyThread_get_thread_ident(), aSemaphore));
}