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# Class Date supplies date objects that support date arithmetic.
#
# Date(month,day,year) returns a Date object. An instance prints as,
# e.g., 'Mon 16 Aug 1993'.
#
# Addition, subtraction, comparison operators, min, max, and sorting
# all work as expected for date objects: int+date or date+int returns
# the date `int' days from `date'; date+date raises an exception;
# date-int returns the date `int' days before `date'; date2-date1 returns
# an integer, the number of days from date1 to date2; int-date raises an
# exception; date1 < date2 is true iff date1 occurs before date2 (&
# similarly for other comparisons); min(date1,date2) is the earlier of
# the two dates and max(date1,date2) the later; and date objects can be
# used as dictionary keys.
#
# Date objects support one visible method, date.weekday(). This returns
# the day of the week the date falls on, as a string.
#
# Date objects also have 4 read-only data attributes:
# .month in 1..12
# .day in 1..31
# .year int or long int
# .ord the ordinal of the date relative to an arbitrary staring point
#
# The Dates module also supplies function today(), which returns the
# current date as a date object.
#
# Those entranced by calendar trivia will be disappointed, as no attempt
# has been made to accommodate the Julian (etc) system. On the other
# hand, at least this package knows that 2000 is a leap year but 2100
# isn't, and works fine for years with a hundred decimal digits <wink>.
# Tim Peters tim@ksr.com
# not speaking for Kendall Square Research Corp
# Adapted to Python 1.1 (where some hacks to overcome coercion are unnecessary)
# by Guido van Rossum
# Note that as of Python 2.3, a datetime module is included in the stardard
# library.
# vi:set tabsize=8:
_MONTH_NAMES = [ 'January', 'February', 'March', 'April', 'May',
'June', 'July', 'August', 'September', 'October',
'November', 'December' ]
_DAY_NAMES = [ 'Friday', 'Saturday', 'Sunday', 'Monday',
'Tuesday', 'Wednesday', 'Thursday' ]
_DAYS_IN_MONTH = [ 31, 28, 31, 30, 31, 30, 31, 31, 30, 31, 30, 31 ]
_DAYS_BEFORE_MONTH = []
dbm = 0
for dim in _DAYS_IN_MONTH:
_DAYS_BEFORE_MONTH.append(dbm)
dbm = dbm + dim
del dbm, dim
_INT_TYPES = type(1), type(1L)
def _is_leap( year ): # 1 if leap year, else 0
if year % 4 != 0: return 0
if year % 400 == 0: return 1
return year % 100 != 0
def _days_in_year( year ): # number of days in year
return 365 + _is_leap(year)
def _days_before_year( year ): # number of days before year
return year*365L + (year+3)/4 - (year+99)/100 + (year+399)/400
def _days_in_month( month, year ): # number of days in month of year
if month == 2 and _is_leap(year): return 29
return _DAYS_IN_MONTH[month-1]
def _days_before_month( month, year ): # number of days in year before month
return _DAYS_BEFORE_MONTH[month-1] + (month > 2 and _is_leap(year))
def _date2num( date ): # compute ordinal of date.month,day,year
return _days_before_year( date.year ) + \
_days_before_month( date.month, date.year ) + \
date.day
_DI400Y = _days_before_year( 400 ) # number of days in 400 years
def _num2date( n ): # return date with ordinal n
if type(n) not in _INT_TYPES:
raise TypeError, 'argument must be integer: ' + `type(n)`
ans = Date(1,1,1) # arguments irrelevant; just getting a Date obj
del ans.ord, ans.month, ans.day, ans.year # un-initialize it
ans.ord = n
n400 = (n-1)/_DI400Y # # of 400-year blocks preceding
year, n = 400 * n400, n - _DI400Y * n400
more = n / 365
dby = _days_before_year( more )
if dby >= n:
more = more - 1
dby = dby - _days_in_year( more )
year, n = year + more, int(n - dby)
try: year = int(year) # chop to int, if it fits
except (ValueError, OverflowError): pass
month = min( n/29 + 1, 12 )
dbm = _days_before_month( month, year )
if dbm >= n:
month = month - 1
dbm = dbm - _days_in_month( month, year )
ans.month, ans.day, ans.year = month, n-dbm, year
return ans
def _num2day( n ): # return weekday name of day with ordinal n
return _DAY_NAMES[ int(n % 7) ]
class Date:
def __init__( self, month, day, year ):
if not 1 <= month <= 12:
raise ValueError, 'month must be in 1..12: ' + `month`
dim = _days_in_month( month, year )
if not 1 <= day <= dim:
raise ValueError, 'day must be in 1..' + `dim` + ': ' + `day`
self.month, self.day, self.year = month, day, year
self.ord = _date2num( self )
# don't allow setting existing attributes
def __setattr__( self, name, value ):
if self.__dict__.has_key(name):
raise AttributeError, 'read-only attribute ' + name
self.__dict__[name] = value
def __cmp__( self, other ):
return cmp( self.ord, other.ord )
# define a hash function so dates can be used as dictionary keys
def __hash__( self ):
return hash( self.ord )
# print as, e.g., Mon 16 Aug 1993
def __repr__( self ):
return '%.3s %2d %.3s ' % (
self.weekday(),
self.day,
_MONTH_NAMES[self.month-1] ) + `self.year`
# Python 1.1 coerces neither int+date nor date+int
def __add__( self, n ):
if type(n) not in _INT_TYPES:
raise TypeError, 'can\'t add ' + `type(n)` + ' to date'
return _num2date( self.ord + n )
__radd__ = __add__ # handle int+date
# Python 1.1 coerces neither date-int nor date-date
def __sub__( self, other ):
if type(other) in _INT_TYPES: # date-int
return _num2date( self.ord - other )
else:
return self.ord - other.ord # date-date
# complain about int-date
def __rsub__( self, other ):
raise TypeError, 'Can\'t subtract date from integer'
def weekday( self ):
return _num2day( self.ord )
def today():
import time
local = time.localtime(time.time())
return Date( local[1], local[2], local[0] )
DateTestError = 'DateTestError'
def test( firstyear, lastyear ):
a = Date(9,30,1913)
b = Date(9,30,1914)
if `a` != 'Tue 30 Sep 1913':
raise DateTestError, '__repr__ failure'
if (not a < b) or a == b or a > b or b != b:
raise DateTestError, '__cmp__ failure'
if a+365 != b or 365+a != b:
raise DateTestError, '__add__ failure'
if b-a != 365 or b-365 != a:
raise DateTestError, '__sub__ failure'
try:
x = 1 - a
raise DateTestError, 'int-date should have failed'
except TypeError:
pass
try:
x = a + b
raise DateTestError, 'date+date should have failed'
except TypeError:
pass
if a.weekday() != 'Tuesday':
raise DateTestError, 'weekday() failure'
if max(a,b) is not b or min(a,b) is not a:
raise DateTestError, 'min/max failure'
d = {a-1:b, b:a+1}
if d[b-366] != b or d[a+(b-a)] != Date(10,1,1913):
raise DateTestError, 'dictionary failure'
# verify date<->number conversions for first and last days for
# all years in firstyear .. lastyear
lord = _days_before_year( firstyear )
y = firstyear
while y <= lastyear:
ford = lord + 1
lord = ford + _days_in_year(y) - 1
fd, ld = Date(1,1,y), Date(12,31,y)
if (fd.ord,ld.ord) != (ford,lord):
raise DateTestError, ('date->num failed', y)
fd, ld = _num2date(ford), _num2date(lord)
if (1,1,y,12,31,y) != \
(fd.month,fd.day,fd.year,ld.month,ld.day,ld.year):
raise DateTestError, ('num->date failed', y)
y = y + 1
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