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# Routines to force "compilation" of all .py files in a directory
# tree or on sys.path. By default recursion is pruned at a depth of
# 10 and the current directory, if it occurs in sys.path, is skipped.
# When called as a script, compiles argument directories, or sys.path
# if no arguments.
# After a similar module by Sjoerd Mullender.
import os
import sys
import py_compile
def compile_dir(dir, maxlevels = 10):
print 'Listing', dir, '...'
try:
names = os.listdir(dir)
except os.error:
print "Can't list", dir
names = []
names.sort()
for name in names:
fullname = os.path.join(dir, name)
if os.path.isfile(fullname):
head, tail = name[:-3], name[-3:]
if tail == '.py':
print 'Compiling', fullname, '...'
try:
py_compile.compile(fullname)
except KeyboardInterrupt:
del names[:]
print '\n[interrupt]'
break
except:
if type(sys.exc_type) == type(''):
exc_type_name = sys.exc_type
else: exc_type_name = sys.exc_type.__name__
print 'Sorry:', exc_type_name + ':',
print sys.exc_value
elif maxlevels > 0 and \
name != os.curdir and name != os.pardir and \
os.path.isdir(fullname) and \
not os.path.islink(fullname):
compile_dir(fullname, maxlevels - 1)
def compile_path(skip_curdir = 1):
for dir in sys.path:
if dir == os.curdir and skip_curdir:
print 'Skipping current directory'
else:
compile_dir(dir, 0)
def main():
import getopt
try:
opts, args = getopt.getopt(sys.argv[1:], 'l')
except getopt.error, msg:
print msg
print "usage: compileall [-l] [directory ...]"
print "-l: don't recurse down"
print "if no arguments, -l sys.path is assumed"
maxlevels = 10
for o, a in opts:
if o == '-l': maxlevels = 0
if args:
for dir in sys.argv[1:]:
compile_dir(dir, maxlevels)
else:
compile_path()
if __name__ == '__main__':
main()
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