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from test_support import verbose, verify
import sys
import new
class Eggs:
def get_yolks(self):
return self.yolks
print 'new.module()'
m = new.module('Spam')
if verbose:
print m
m.Eggs = Eggs
sys.modules['Spam'] = m
import Spam
def get_more_yolks(self):
return self.yolks + 3
print 'new.classobj()'
C = new.classobj('Spam', (Spam.Eggs,), {'get_more_yolks': get_more_yolks})
if verbose:
print C
print 'new.instance()'
c = new.instance(C, {'yolks': 3})
if verbose:
print c
o = new.instance(C)
verify(o.__dict__ == {},
"new __dict__ should be empty")
del o
o = new.instance(C, None)
verify(o.__dict__ == {},
"new __dict__ should be empty")
del o
def break_yolks(self):
self.yolks = self.yolks - 2
print 'new.instancemethod()'
im = new.instancemethod(break_yolks, c, C)
if verbose:
print im
verify(c.get_yolks() == 3 and c.get_more_yolks() == 6,
'Broken call of hand-crafted class instance')
im()
verify(c.get_yolks() == 1 and c.get_more_yolks() == 4,
'Broken call of hand-crafted instance method')
# It's unclear what the semantics should be for a code object compiled at
# module scope, but bound and run in a function. In CPython, `c' is global
# (by accident?) while in Jython, `c' is local. The intent of the test
# clearly is to make `c' global, so let's be explicit about it.
codestr = '''
global c
a = 1
b = 2
c = a + b
'''
ccode = compile(codestr, '<string>', 'exec')
# Jython doesn't have a __builtins__, so use a portable alternative
import __builtin__
g = {'c': 0, '__builtins__': __builtin__}
# this test could be more robust
print 'new.function()'
func = new.function(ccode, g)
if verbose:
print func
func()
verify(g['c'] == 3,
'Could not create a proper function object')
print 'new.code()'
# bogus test of new.code()
# Note: Jython will never have new.code()
if hasattr(new, 'code'):
d = new.code(3, 3, 3, 3, codestr, (), (), (),
"<string>", "<name>", 1, "", (), ())
# test backwards-compatibility version with no freevars or cellvars
d = new.code(3, 3, 3, 3, codestr, (), (), (),
"<string>", "<name>", 1, "")
if verbose:
print d
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