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"""Add a 'PYC ' resource named "__main__" to a resource file.
This first puts up a dialog asking for a Python source file ('TEXT'),
then one asking for an existing destination file ('APPL' or 'rsrc').
It compiles the Python source into a code object, marshals it into a string,
prefixes the string with a .pyc header, and turns it into a resource,
which is then written to the destination.
If the destination already contains a resource with the same name and type,
it is overwritten.
"""
import marshal
import imp
import macfs
from Res import *
# .pyc file (and 'PYC ' resource magic number)
MAGIC = imp.get_magic()
# Complete specification of our resource
RESTYPE = 'PYC '
RESID = 128
RESNAME = '__main__'
# OpenResFile mode parameters
READ = 1
WRITE = 2
def main():
# Ask for source text
srcfss, ok = macfs.StandardGetFile('TEXT')
if not ok: return
# Read the source and compile it
# (there's no point asking for a destination if it has a syntax error)
filename = srcfss.as_pathname()
fp = open(filename)
text = fp.read()
fp.close()
code = compile(text, filename, "exec")
# Ask for destination file
dstfss, ok = macfs.StandardGetFile('APPL', 'rsrc')
if not ok: return
# Create the raw data for the resource from the code object
data = marshal.dumps(code)
del code
data = (MAGIC + '\0\0\0\0') + data
# Open the resource file
fnum = FSpOpenResFile(dstfss.as_pathname(), WRITE)
# Delete any existing resource with name __main__ or number 128
try:
res = Get1NamedResource(RESTYPE, RESNAME)
res.RmveResource()
except Error:
pass
try:
res = Get1Resource(RESTYPE, RESID)
res.RmveResource()
except Error:
pass
# Create the resource and write it
res = Resource(data)
res.AddResource(RESTYPE, RESID, RESNAME)
# XXX Are the following two calls needed?
res.WriteResource()
res.ReleaseResource()
# Close the resource file
CloseResFile(fnum)
if __name__ == '__main__':
main()
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