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author | Miss Islington (bot) <31488909+miss-islington@users.noreply.github.com> | 2017-11-25 05:03:04 (GMT) |
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committer | Mariatta <Mariatta@users.noreply.github.com> | 2017-11-25 05:03:04 (GMT) |
commit | 3e60747025edc34b503397ab8211be59cfdd05cd (patch) | |
tree | e5bf6ad9600d4711edfe6fcc5665e5303abea72a | |
parent | dde38b9cb3ff24f2f1f17cb681d30741e0090f51 (diff) | |
download | cpython-3e60747025edc34b503397ab8211be59cfdd05cd.zip cpython-3e60747025edc34b503397ab8211be59cfdd05cd.tar.gz cpython-3e60747025edc34b503397ab8211be59cfdd05cd.tar.bz2 |
bpo-30004: Fix the code example of using group in Regex Howto Docs (GH-4443) (GH-4554)
The provided code example was supposed to find repeated words, however it returned false results.
(cherry picked from commit 610e5afdcbe3eca906ef32f4e0364e20e1b1ad23)
-rw-r--r-- | Doc/howto/regex.rst | 6 |
1 files changed, 3 insertions, 3 deletions
diff --git a/Doc/howto/regex.rst b/Doc/howto/regex.rst index 7ff4563..eef6347 100644 --- a/Doc/howto/regex.rst +++ b/Doc/howto/regex.rst @@ -844,7 +844,7 @@ backreferences in a RE. For example, the following RE detects doubled words in a string. :: - >>> p = re.compile(r'(\b\w+)\s+\1') + >>> p = re.compile(r'\b(\w+)\s+\1\b') >>> p.search('Paris in the the spring').group() 'the the' @@ -943,9 +943,9 @@ number of the group. There's naturally a variant that uses the group name instead of the number. This is another Python extension: ``(?P=name)`` indicates that the contents of the group called *name* should again be matched at the current point. The regular expression for finding doubled words, -``(\b\w+)\s+\1`` can also be written as ``(?P<word>\b\w+)\s+(?P=word)``:: +``\b(\w+)\s+\1\b`` can also be written as ``\b(?P<word>\w+)\s+(?P=word)\b``:: - >>> p = re.compile(r'(?P<word>\b\w+)\s+(?P=word)') + >>> p = re.compile(r'\b(?P<word>\w+)\s+(?P=word)\b') >>> p.search('Paris in the the spring').group() 'the the' |