Warning from preprocessor regarding binary literals

When having a line like:
```
#if (JITTERLISP_FIXNUM_TAG_BIN  == 0)
```
with
```
#define JITTERLISP_FIXNUM_TAG_BIN           0b0000
```
we get the warning:
```
warning: preprocessing issue while doing constant expression evaluation: syntax error: input=' ( 0b0000   == 0)'
```

The equivalent hexadecimal / octal / decimal versions are OK, the handling for the binary was missing.

(Found by Fossies in the poke package).

1 files changed, 10 insertions, 0 deletions

diff --git a/src/cppvalue.cpp b/src/cppvalue.cpp
index 31f0ab5..b6e7f65 100644
--- a/src/cppvalue.cpp
+++ b/src/cppvalue.cpp
@@ -51,6 +51,16 @@ CPPValue parseHexadecimal(const std::string& token)
   return CPPValue(val);
 }
 
+CPPValue parseBinary(const std::string& token)
+{
+  long val = 0;
+  for (const char *p = token.c_str(); *p != 0; p++)
+  {
+    if (*p >= '0' && *p <= '1') val = val * 2 + *p - '0';
+  }
+  return CPPValue(val);
+}
+
 CPPValue parseCharacter(const std::string& token) // does not work for '\n' and the alike
 {
   if (token[1]=='\\')