Ensure that the type is not registered as a typedef

When qRegisterMetaType() is given a dummy parameter as 0 then it will
try to register it as a typedef and not a type.  Changing it to be -1
for the dummy parameter will ensure that it is not registered as a
typedef.

Task-number: QTBUG-18555
Change-Id: I18606bb1e53a334256658cc5b8d8a13c0d6617a1
Reviewed-by: Martin Petersson
Reviewed-by: Martin Petersson <Martin.Petersson@nokia.com>

1 files changed, 1 insertions, 1 deletions

diff --git a/src/activeqt/control/qaxserver.cpp b/src/activeqt/control/qaxserver.cpp
index f641660..8b6de43 100644
--- a/src/activeqt/control/qaxserver.cpp
+++ b/src/activeqt/control/qaxserver.cpp
@@ -91,7 +91,7 @@ QAxFactory *qAxFactory()
         QStringList keys(qax_factory->featureList());
         for (int i = 0; i < keys.count(); ++i) {
             QString key(keys.at(i));
-            qRegisterMetaType((key + QLatin1Char('*')).toLatin1(), (void**)0);
+            qRegisterMetaType((key + QLatin1Char('*')).toLatin1(), (void**)(quintptr)-1);
         }
     }
     return qax_factory;