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authorBenjamin Peterson <benjamin@python.org>2009-06-03 03:13:30 (GMT)
committerBenjamin Peterson <benjamin@python.org>2009-06-03 03:13:30 (GMT)
commit3db5e7be1cf61756e89c40efcc1e24f00f33425b (patch)
treedc4beb3543065c6749324de4aed4b329b36b4521
parentb2b35af7512c9b62fb4060973f7227ded4163d70 (diff)
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range() doesn't return a list
-rw-r--r--Doc/reference/compound_stmts.rst2
1 files changed, 1 insertions, 1 deletions
diff --git a/Doc/reference/compound_stmts.rst b/Doc/reference/compound_stmts.rst
index 214143b..016ccbb 100644
--- a/Doc/reference/compound_stmts.rst
+++ b/Doc/reference/compound_stmts.rst
@@ -182,7 +182,7 @@ the next item assigned to it.
Names in the target list are not deleted when the loop is finished, but if the
sequence is empty, it will not have been assigned to at all by the loop. Hint:
the built-in function :func:`range` returns an iterator of integers suitable to
-emulate the effect of Pascal's ``for i := a to b do``; e.g., ``range(3)``
+emulate the effect of Pascal's ``for i := a to b do``; e.g., ``list(range(3))``
returns the list ``[0, 1, 2]``.
.. note::