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| author | Georg Brandl <georg@python.org> | 2008-04-26 18:25:43 (GMT) |
|---|---|---|
| committer | Georg Brandl <georg@python.org> | 2008-04-26 18:25:43 (GMT) |
| commit | a3bb57caee0c05536f5cc37e91d7f1c2cefaa620 (patch) | |
| tree | 30139f87c113b8a765422cd8134bb0b12de76cc3 | |
| parent | 14204ad982309ae1ea5160b184709f10e7d22547 (diff) | |
| download | cpython-a3bb57caee0c05536f5cc37e91d7f1c2cefaa620.zip cpython-a3bb57caee0c05536f5cc37e91d7f1c2cefaa620.tar.gz cpython-a3bb57caee0c05536f5cc37e91d7f1c2cefaa620.tar.bz2 | |
#2668: nit in apply() docs.
| -rw-r--r-- | Doc/library/functions.rst | 2 |
1 files changed, 1 insertions, 1 deletions
diff --git a/Doc/library/functions.rst b/Doc/library/functions.rst index b26655e..4ec03c8 100644 --- a/Doc/library/functions.rst +++ b/Doc/library/functions.rst @@ -1354,7 +1354,7 @@ bypass these functions without concerns about missing something important. present, it must be a dictionary whose keys are strings. It specifies keyword arguments to be added to the end of the argument list. Calling :func:`apply` is different from just calling ``function(args)``, since in that case there is - always exactly one argument. The use of :func:`apply` is exactly equivalent to + always exactly one argument. The use of :func:`apply` is equivalent to ``function(*args, **keywords)``. .. deprecated:: 2.3 |