gh-101825: Clarify that as_integer_ratio() output is always normalized (#101843)

Make docstrings for `as_integer_ratio` consistent across types, and document that
the returned pair is always normalized (coprime integers, with positive denominator).

---------

Co-authored-by: Owain Davies <116417456+OTheDev@users.noreply.github.com>
Co-authored-by: Mark Dickinson <dickinsm@gmail.com>

1 files changed, 3 insertions, 3 deletions

diff --git a/Doc/library/stdtypes.rst b/Doc/library/stdtypes.rst
index 41947d6..1240f80 100644
--- a/Doc/library/stdtypes.rst
+++ b/Doc/library/stdtypes.rst
@@ -602,8 +602,8 @@ class`. In addition, it provides a few more methods:
 
 .. method:: int.as_integer_ratio()
 
-   Return a pair of integers whose ratio is exactly equal to the original
-   integer and with a positive denominator. The integer ratio of integers
+   Return a pair of integers whose ratio is equal to the original
+   integer and has a positive denominator.  The integer ratio of integers
    (whole numbers) is always the integer as the numerator and ``1`` as the
    denominator.
 
@@ -624,7 +624,7 @@ class`. float also has the following additional methods.
 .. method:: float.as_integer_ratio()
 
    Return a pair of integers whose ratio is exactly equal to the
-   original float and with a positive denominator.  Raises
+   original float. The ratio is in lowest terms and has a positive denominator.  Raises
    :exc:`OverflowError` on infinities and a :exc:`ValueError` on
    NaNs.