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author | Guido van Rossum <guido@python.org> | 1991-01-23 13:41:31 (GMT) |
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committer | Guido van Rossum <guido@python.org> | 1991-01-23 13:41:31 (GMT) |
commit | 7df0c16b619767ea4db0fd5a684723ac1458ecb0 (patch) | |
tree | 0c212c2ec91394efa0dbd8d2a7b9a464ae8c8866 /Lib/lib-stdwin | |
parent | b3fa13cef7fc0add41da0ed22fd47c388c3a1bf1 (diff) | |
download | cpython-7df0c16b619767ea4db0fd5a684723ac1458ecb0.zip cpython-7df0c16b619767ea4db0fd5a684723ac1458ecb0.tar.gz cpython-7df0c16b619767ea4db0fd5a684723ac1458ecb0.tar.bz2 |
Initial revision
Diffstat (limited to 'Lib/lib-stdwin')
-rw-r--r-- | Lib/lib-stdwin/CSplit.py | 70 |
1 files changed, 70 insertions, 0 deletions
diff --git a/Lib/lib-stdwin/CSplit.py b/Lib/lib-stdwin/CSplit.py new file mode 100644 index 0000000..03559c1 --- /dev/null +++ b/Lib/lib-stdwin/CSplit.py @@ -0,0 +1,70 @@ +# A CSplit is a Clock-shaped split: the children are grouped in a circle. +# The numbering is a little different from a real clock: the 12 o'clock +# position is called 0, not 12. This is a little easier since Python +# usually counts from zero. (BTW, there needn't be exactly 12 children.) + + +from math import pi, sin, cos +from Split import Split + +class CSplit() = Split(): + # + def minsize(self, m): + # Since things look best if the children are spaced evenly + # along the circle (and often all children have the same + # size anyway) we compute the max child size and assume + # this is each child's size. + width, height = 0, 0 + for child in self.children: + wi, he = child.minsize(m) + width = max(width, wi) + height = max(height, he) + # In approximation, the diameter of the circle we need is + # (diameter of box) * (#children) / pi. + # We approximate pi by 3 (so we slightly overestimate + # our minimal size requirements -- not so bad). + # Because the boxes stick out of the circle we add the + # box size to each dimension. + # Because we really deal with ellipses, do everything + # separate in each dimension. + n = len(self.children) + return width + (width*n + 2)/3, height + (height*n + 2)/3 + # + def getbounds(self): + return self.bounds + # + def setbounds(self, bounds): + self.bounds = bounds + # Place the children. This involves some math. + # Compute center positions for children as if they were + # ellipses with a diameter about 1/N times the + # circumference of the big ellipse. + # (There is some rounding involved to make it look + # reasonable for small and large N alike.) + # XXX One day Python will have automatic conversions... + n = len(self.children) + fn = float(n) + if n = 0: return + (left, top), (right, bottom) = bounds + width, height = right-left, bottom-top + child_width, child_height = width*3/(n+4), height*3/(n+4) + half_width, half_height = \ + float(width-child_width)/2.0, \ + float(height-child_height)/2.0 + center_h, center_v = center = (left+right)/2, (top+bottom)/2 + fch, fcv = float(center_h), float(center_v) + alpha = 2.0 * pi / fn + for i in range(n): + child = self.children[i] + fi = float(i) + fh, fv = \ + fch + half_width*sin(fi*alpha), \ + fcv - half_height*cos(fi*alpha) + left, top = \ + int(fh) - child_width/2, \ + int(fv) - child_height/2 + right, bottom = \ + left + child_width, \ + top + child_height + child.setbounds((left, top), (right, bottom)) + # |