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authorMark Dickinson <dickinsm@gmail.com>2013-10-13 09:55:15 (GMT)
committerMark Dickinson <dickinsm@gmail.com>2013-10-13 09:55:15 (GMT)
commit36f6e2c9e0cfd1bab83d6ae1d192d4951ccc0160 (patch)
tree3acc2a620f4d478d4d2af2572f454aa6ebd9be49 /Modules
parent65e30a2db5772c223bb9a09e756dee743d05cc04 (diff)
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Issue #18739: Fix inconsistent results from math.log(n) and math.log(long(n))
Diffstat (limited to 'Modules')
-rw-r--r--Modules/mathmodule.c34
1 files changed, 22 insertions, 12 deletions
diff --git a/Modules/mathmodule.c b/Modules/mathmodule.c
index cd74b0d..845fb9b 100644
--- a/Modules/mathmodule.c
+++ b/Modules/mathmodule.c
@@ -1277,23 +1277,33 @@ loghelper(PyObject* arg, double (*func)(double), char *funcname)
{
/* If it is long, do it ourselves. */
if (PyLong_Check(arg)) {
- double x;
+ double x, result;
Py_ssize_t e;
- x = _PyLong_Frexp((PyLongObject *)arg, &e);
- if (x == -1.0 && PyErr_Occurred())
- return NULL;
- if (x <= 0.0) {
+
+ /* Negative or zero inputs give a ValueError. */
+ if (Py_SIZE(arg) <= 0) {
PyErr_SetString(PyExc_ValueError,
"math domain error");
return NULL;
}
- /* Special case for log(1), to make sure we get an
- exact result there. */
- if (e == 1 && x == 0.5)
- return PyFloat_FromDouble(0.0);
- /* Value is ~= x * 2**e, so the log ~= log(x) + log(2) * e. */
- x = func(x) + func(2.0) * e;
- return PyFloat_FromDouble(x);
+
+ x = PyLong_AsDouble(arg);
+ if (x == -1.0 && PyErr_Occurred()) {
+ if (!PyErr_ExceptionMatches(PyExc_OverflowError))
+ return NULL;
+ /* Here the conversion to double overflowed, but it's possible
+ to compute the log anyway. Clear the exception and continue. */
+ PyErr_Clear();
+ x = _PyLong_Frexp((PyLongObject *)arg, &e);
+ if (x == -1.0 && PyErr_Occurred())
+ return NULL;
+ /* Value is ~= x * 2**e, so the log ~= log(x) + log(2) * e. */
+ result = func(x) + func(2.0) * e;
+ }
+ else
+ /* Successfully converted x to a double. */
+ result = func(x);
+ return PyFloat_FromDouble(result);
}
/* Else let libm handle it by itself. */